this is because there is a 1/2 chance of there being one head and one tail, and only 1/4 each of there being two heads or two tails:
coin 1: h (1/2 chance) x coin 2: h (1/2 chance) = 1/4 chance
coin 1: t (1/2 chance) x coin 2: h (1/2 chance) = 1/4 chance
coin 1: h (1/2 chance) x coin 2: t (1/2 chance) = 1/4 chance
coin 1: t (1/2 chance) x coin 2: t (1/2 chance) = 1/4 chance
coin 1 being heads and coin 2 being tails is the same vice versa, so:
50 tosses x (1/4 + 1/4) = 25 times
the theoretical probability of ht or th when two coins are tossed is 1/2 . (all possible outcomes are hh,tt,ht,th). this means that when we run the experiment repeatedly we expect to get the desired result 1/2 of the time. since you intend to toss the coins 40 times, 20 are expected.
sample space for two coins tossed is: hh ht th tt therefore at most one head is ht th tt or 3/4 or 0.75.
285 out of 500
the probability is 3/4.
out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 tails & 1 head. they are: ttth, ttht, thtt, and httt.
when two fair coins are tossed, you have the following possible outcomes: hh, ht, th, tt. so, at most implies that you get either i) zero heads or ii) one head. from the possible outcomes we see that 3 times we satisify the outcome. thus, probability of at most one head is 3/4.
is it 50% or 100% dang, i just confused myself. what if you toss 3 coins all at the same time... what's the probability of getting a head then, is it > 100% ? doh!
ttt, tth, tht, htt
3/8 * * * * * that is the probability of getting exactly 1h. the prob of getting one (or more) head is 7/8
the probability is 1/4
at least two heads with two coins? you can't get more.there are 4 different outcomes:tail-tail, head-tail, tail-head and head-head.you can use one out of four - which gives us the probability 1/4 = 0.25 = 25%
there can be only three combo's ------ head n tail,,,,,,,, tail n tail,,,,,,,,,,,,,, head n head
255/256 (complement formula)
1/2 or 50% (1/8 prob of 0h + 3/8 prob of 1h)
the probability of getting a head on each occasion if a coin is tossed five times is equal to 1/2 x 1/2 x 1/2 x 1/2 x 1/2 (that is, 1/25) = 1/32 or one in thirty-two. the probability of getting a head on the fifth toss is 1/2. all other tosses are independent of the fifth toss. the probability of getting at least one head when tossing the coin 5 times: since there are 32 possible combinations and only one of those combinations is all tails you could expect to toss a combination with a head 31/32 times. the probability is 0.96875.
assuming that it is a fair coin, the probability is 0.9990
0.5, 1/2, 50% the probability for heads versus tails does not change based on the amount of times the coin is tossed. it will always be a 50% chance.
it means that if the coin were tossed an infinite number of times, half of the tosses would come up heads and half would be tails.
in three tosses there can be four possible outcomes: three heads, three tails, two heads and one tail, and one head and two tails. ^^^that is wronga coin is tossed n times. there are 2 possibilities when you toss a coin: heads and tails.so the formula is 2^n (thats to the n power)a coin tossed 3 times has 2^3=8 possible outcomes:head head headhead head tailhead tail headtail head headtail tail headhead tail tailtail head tailtail tail tailthere they are!
the probability of getting one head and one tail on three flips of a coin is 1/9
there are 4 events: 3 heads, 2 heads 1 tail, 1 head 2 tails, and 3 tails.